(x^-1y^3z^0/x^4y^8)^-2

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Solution for (x^-1y^3z^0/x^4y^8)^-2 equation:


D( x )

x^4 = 0

x = 0

((z^0*x^-1*y^3)/(x^4))*y^8 = 0

x^4 = 0

x^4 = 0

1*x^4 = 0 // : 1

x^4 = 0

x = 0

x = 0

x = 0

((z^0*x^-1*y^3)/(x^4))*y^8 = 0

((z^0*x^-1*y^3)/(x^4))*y^8 = 0

((x^-1*y^3)/(x^4))*y^8 = 0

x^-5*y^11 = 0 // : y^11

x^-5 = 0

x należy do O

x in (-oo:0) U (0:+oo)

(((z^0*x^-1*y^3)/(x^4))*y^8)^-2 = 0

(((x^-1*y^3)/(x^4))*y^8)^-2 = 0

x^10*y^-22 = 0 // : y^-22

x^10 = 0

x = 0

x in { 0}

x belongs to the empty set

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